2[5c+2]-2c=3[2c+3]+7

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Solution for 2[5c+2]-2c=3[2c+3]+7 equation: 


Simplifying
2[5c + 2] + -2c = 3[2c + 3] + 7

Reorder the terms:
2[2 + 5c] + -2c = 3[2c + 3] + 7
[2 * 2 + 5c * 2] + -2c = 3[2c + 3] + 7
[4 + 10c] + -2c = 3[2c + 3] + 7

Combine like terms: 10c + -2c = 8c
4 + 8c = 3[2c + 3] + 7

Reorder the terms:
4 + 8c = 3[3 + 2c] + 7
4 + 8c = [3 * 3 + 2c * 3] + 7
4 + 8c = [9 + 6c] + 7

Reorder the terms:
4 + 8c = 9 + 7 + 6c

Combine like terms: 9 + 7 = 16
4 + 8c = 16 + 6c

Solving
4 + 8c = 16 + 6c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-6c' to each side of the equation.
4 + 8c + -6c = 16 + 6c + -6c

Combine like terms: 8c + -6c = 2c
4 + 2c = 16 + 6c + -6c

Combine like terms: 6c + -6c = 0
4 + 2c = 16 + 0
4 + 2c = 16

Add '-4' to each side of the equation.
4 + -4 + 2c = 16 + -4

Combine like terms: 4 + -4 = 0
0 + 2c = 16 + -4
2c = 16 + -4

Combine like terms: 16 + -4 = 12
2c = 12

Divide each side by '2'.
c = 6

Simplifying
c = 6

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